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Reverse Nodes in k-Group (hard)
Problem Statement
Given the head
of a linked list, reverse each k node of the list at a time and return the modified list.
Here, k
is a positive integer and is less than or equal to the length of the linked list. If the number of nodes is not a multiple of k, the remaining nodes at the end should stay as they are.
Note: You can only change the nodes themselves, not the values inside them.
Examples
-
Example 1:
- Input: head = [1, 2, 3, 4, 5, 6], k = 3
- Expected Output: [3, 2, 1, 6, 5, 4]
- Justification: The list is reversed in groups of three. First group [1, 2, 3] becomes [3, 2, 1] and the second group [4, 5, 6] becomes [6, 5, 4].
-
Example 2:
- Input: head = [1, 2, 3, 4, 5], k = 2
- Expected Output: [2, 1, 4, 3, 5]
- Justification: The list is reversed in groups of two. First group [1, 2] becomes [2, 1] and the second group [3, 4] becomes [4, 3]. The last node [5] remains unchanged.
-
Example 3:
- Input: head = [1, 2, 3, 4, 5, 6, 7], k = 4
- Expected Output: [4, 3, 2, 1, 5, 6, 7]
- Justification: The list is reversed in groups of four. First group [1, 2, 3, 4] becomes [4, 3, 2, 1]. The remaining nodes [5, 6, 7] are left as they are because their count is less than k.
Constraints:
- The number of nodes in the list is
n
. 1 <= k <= n <= 5000
0 <= Node.val <= 1000
Try it yourself
Try solving this question here:
Python3
Python3
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