## Problem Statement There are `n` kids with candies. You are given a `candies` array containing integers, where `candies[i]` denotes the number of candies the i^th kid has, and an integer `extraCandies`, represents the number of extra candies that you have. Return a boolean array result of length `n`, where `result[i]` is `true` if, after giving all the `extraCandies` to the i^th kid, he/she will have the maximum number of candies among all the kids, or `false` otherwise. **Note:** Multiple kids can have the maximum number of candies. ### Examples **Example 1:** - **Input:** candies = [7, 3, 9, 2, 4], extraCandies = 5 - **Expected Output:** [true, false, true, false, true] - **Justification:** If you give all extraCandies to: - Kid 1, they will have 7 + 5 = 12 candies, which is the maximum among the kids. - Kid 2, they will have 3 + 5 = 8 candies, which is not the greatest among the kids. - Kid 3, they will have 9 + 5 = 14 candies, which is the greatest among the kids. - Kid 4, they will have 2 + 5 = 7 candies, which is not the greatest among the kids. - Kid 5, they will have 4 + 5 = 9 candies, which is the greatest among the kids. **Example 2:** - **Input:** candies = [5, 8, 6, 4, 2], extraCandies = 3 - **Expected Output:** [true, true, true, false, false] - **Justification:** Giving 3 extra candies to the first, second, and third kid will make their totals 8, 11, and 9 respectively, which are the highest. Other kids can't reach these totals. **Example 3:** - **Input:** candies = [1, 2, 3, 4, 5], extraCandies = 4 - **Expected Output:** [true, true, true, true, true] - **Justification:** Giving 4 extra candies to each kid will make their totals 5, 6, 7, 8, and 9 respectively, which means they all can potentially have the highest number of candies. **Constraints:** - `n == candies.length` - `2 <= n <= 100` - `1 <= candies[i] <= 100` - `1 <= extraCandies <= 50` ## Solution To solve this problem, we first need to find the maximum number of candies that any kid currently has. Then, for each kid, we check if giving them all the extra candies would make their total number of candies greater than or equal to this maximum value. This approach ensures that we only need to traverse the list of candies twice, making it efficient. This method works because it directly addresses the problem's requirement by focusing on the condition needed to determine if a kid can have the highest number of candies. By first finding the current highest number of candies, we simplify the subsequent checks for each kid, ensuring the solution is both straightforward and efficient. ### Step-by-Step Algorithm - Find the maximum number of candies any kid currently has. - Create an empty list to store the results. - For each kid, calculate their total candies if they receive all the extra candies. - Compare this total to the maximum number of candies. - If the total is greater than or equal to the maximum, add true to the result list. - Otherwise, add false to the result list. - Return the result list. ### Algorithm Walkthrough **Input:** candies = [7, 3, 9, 2, 4], extraCandies = 5 - Find the maximum candies: `maxCandies = 9` - Initialize result list: `result = []` - For each kid: - Kid 1: 7 + 5 = 12 >= 9 (true) - Kid 2: 3 + 5 = 8 < 9(false) - Kid 3: 9 + 5 = 14 >= 9(true) - Kid 4: 2 + 5 = 7 < 9(false) - Kid 5: 4 + 5 = 9 >= 9(true) - Return: `[true, false, true, false, true]`