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Word Pattern (easy)
Problem Statement
Given a pattern
and a string s
, return true
if the string s
follows the same pattern
.
Here, the following the pattern means each character
in the pattern should map
to a single word
in s
, and each word in s
should map to a single character
in the pattern.
Examples
Example 1:
- Input: pattern =
"eegg"
, s ="dog dog cat cat"
- Output:
true
- Explanation: The pattern "eegg" corresponds to the words "dog dog cat cat". Both 'e's map to "dog" and both 'g's map to "cat".
Example 2:
- Input: pattern =
"abca"
, s ="one two three four"
- Output:
false
- Explanation: Here,
a
maps to the"one"
and"four"
both. So, the string doesn't follow the same pattern.
Example 3:
- Input: pattern =
"abacac"
, s ="dog cat dog mouse dog mouse"
- Output:
true
- Explanation: The pattern "abacac" corresponds to the words "dog cat dog mouse dog mouse". 'a' maps to "dog", 'b' maps to "cat", and 'c' maps to "mouse".
Constraints:
- 1 <= pattern.length <= 300
- pattern contains only lower-case English letters.
- 1 <= s.length <= 3000
s
contains only lowercase English letters and spaces ' '.s
does not contain any leading or trailing spaces.- All the words in s are separated by a single space.
Try it yourself
Try solving this question here:
Python3
Python3
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