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Problem Statement
Given two binary trees, root1
and root2
, merge them into a single, new binary tree.
If two nodes from the given trees share the same position, their values should be summed up in the resulting tree. If a node exists in one tree but not in the other, the resulting tree should have a node at the same position with the value from the existing node.
Examples
Example 1:
Trees:
Tree 1: 1 Tree 2: 1
/ \ / \
3 2 2 3
Merged: 2
/ \
5 5
Justification:
The root nodes of both trees have the value 1
, so the merged tree's root has a value of 1 + 1 = 2
.
For the left child, 3 + 2 = 5
and for the right child, 2 + 3 = 5
.
Example 2:
Trees:
Tree 1: 5 Tree 2: 3
/ \ / \
4 7 2 6
Merged: 8
/ \
6 13
Justification:
The root nodes have values 5
and 3
respectively. So, the merged tree's root value becomes 5 + 3 = 8
.
The left child is 4 + 2 = 6
and the right child is 7 + 6 = 13
.
Example 3:
Trees:
Tree 1: 2 Tree 2: 2
\ /
5 3
Merged: 4
/ \
3 5
Justification:
The root nodes have values 2
each, so the merged tree's root value is 2 + 2 = 4
.
Tree 1 doesn't have a left child, so we take the left child of Tree 2 as it is, which is 3
.
Similarly, Tree 2 doesn't have a right child, so the merged tree's right child is the same as Tree 1, which is 5
.
Example 4:
Trees:
Tree 1: 10 Tree 2: 10
/ \ / \
5 15 6 16
Merged: 20
/ \
11 31
Justification:
The root nodes have the value 10
, so they add up to 20
for the merged tree.
The left child values add up to 5 + 6 = 11
and the right child values sum up to 15 + 16 = 31
.
Constraints:
- The number of nodes in the tree is in the range
[0, 2000]
. - -10<sup>4</sup> <= Node.val <= 10<sup>4</sup>
Try it yourself
Try solving this question here:
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