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Problem 3: Row With Maximum Ones(easy)
Problem Statement
Given a binary matrix that has dimensions m * n, consisting of ones and zeros, determine the row that contains the highest number of ones and return two values: the zero-based index of this row and the actual count of ones it possesses.
If there is a tie, i.e., multiple rows contain the same maximum number of ones, we must select the row with the lowest index.
Examples
Example 1:
- Input:
[[1, 0], [1, 1], [0, 1]]
- Expected Output:
[1, 2]
- Justification: The second row
[1, 1]
contains the most ones, so the output is[1, 2]
.
Example 2:
- Input:
[[0, 1, 1], [0, 1, 1], [1, 1, 1]]
- Expected Output:
[2, 3]
- Justification: The third row
[1, 1, 1]
has the most ones, leading to the output[2, 3]
.
Example 3:
- Input:
[[1, 0, 1], [0, 0, 1], [1, 1, 0]]
- Expected Output:
[0, 2]
- Justification: Both the first and third rows contain two ones, but we choose the first due to its lower index, resulting in
[0, 2]
.
Constraints:
m == mat.length
n == mat[i].length
1 <= m, n <= 100
mat[i][j]
is either 0 or 1.
Try it yourself
Try solving this question here:
Python3
Python3
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