while (!stack.empty()) { result = stack.top() + result; stack.pop(); } return result; } }; int main() { Solution sol; // Test cases cout << sol.makeGood("AaBCcdEeff") << endl; // Output: "Bdff" cout << sol.makeGood("abBA") << endl; // Output: "" cout << sol.makeGood("s") << endl; // Output: "s" return 0; } 2a:T5f0,using System; using System.Collections.Generic; using System.Text; public class Solution { // Method to remove adjacent characters with the same letter, but different cases public string makeGood(string s) { Stack stack = new Stack(); // Create a stack to store characters foreach (char c in s) { // Check if the current character matches the last character in the stack // in terms of lowercase, and if they have different cases, remove the last character if (stack.Count > 0 && Char.ToLower(stack.Peek()) == Char.ToLower(c) && stack.Peek() != c) { stack.Pop(); } else { stack.Push(c); // Otherwise, push the current character onto the stack } } StringBuilder sb = new StringBuilder(); foreach (char c in stack) { sb.Append(c); // Build a string from the remaining characters in the stack } // Reverse the StringBuilder content to get the final result char[] arr = sb.ToString().ToCharArray(); Array.Reverse(arr); return new string(arr); // Return the reversed string } public static void Main(string[] args) { Solution solution = new Solution(); Console.WriteLine(solution.makeGood("AaBCcdEeff")); // Output: "Bdff" Console.WriteLine(solution.makeGood("abBA")); // Output: "" Console.WriteLine(solution.makeGood("s")); // Output: "s" } } 2b:T58b,package main import ( "fmt" "strings" ) // Solution struct for holding any needed state type Solution struct{} /