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We could do it without creating new node, but adding the values into one tree from other
Aravind Badiger
Dec 9, 2024
We could do it without creating new node, but adding the values into one tree from other
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Crack Jack16 days ago
# I could have been simpler, but I did something like this: class Solution: def traverse(self, p1, p2, t1, t2, side): if not (t1 or t2): return if t1 and t2: t1.val += t2.val self.traverse(t1, t2, t1.lef...