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Not required pop
venkatlearning11
Dec 11, 2023
Not required pop and stack for this problem, because if you do below condition that would remove start right?
for (char c : s.toCharArray()) { // Loop through each character in the input string if (c != '*') { // If the character is not '*' stack.push(c); // Push (add) the character to the stack } }
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Leopoldo Hernandez2 years ago
You'd still need to get rid of the character that comes after.
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