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Javascript solution
Leszek Kalwa
Sep 28, 2024
Guys,
Either you treat stack as a stack, or as an array. What the heck is line:15 from your js solution? That's clearly accessing something by index.
// While the temporary stack is not empty and the top element // of the temporary stack is greater than the current element, // push elements from the temporary stack back to the original stack. while (tempStack.length && tempStack[tempStack.length - 1] > temp) { stack.push(tempStack.pop()); }
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tai a year ago
I ended up using tempStack.at(-1), sometimes the solution was accepted and sometimes it wasn't - but I agree, javascript arrays don't technically have a "peek" function so I feel like the actual solution would require more lines as you'd need to pop off the top and then...
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