class Solution:
  def findCPS(self, st):
    
    def is_palindrom(s, i, j):
      while i <= j :
        if s[i] != s[j]:
          return False
        i += 1
        j -= 1
      return True

    count = 0
    for i in range(0, len(st)):
      for j in range(i, len(st)):
        if is_palindrom(st, i, j):
            count += 1
    
    return count