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lower space complexity than in suggesgted answer
Adam Slowik
Dec 13, 2025
public int minArrayLength(int[] nums, int k) { // ToDo: Write Your Code Here. int counter = 0; int currentProduct = nums[0]; for (int i = 1; i < nums.length; i++) { if (nums[i] == 0){ return 1; } currentProduct *= nums[i]; if (currentProduct <= k) { counter++; } else { currentProduct = nums[i]; } } return nums.length - counter; }
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