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Find the Town Judge (easy)
Problem Statement
You are given a town with n
people, labeled from 1
to n
. Some people trust others. You need to find out if there is a "town judge". The town judge is someone who:
- Everyone else trusts.
- The town judge trusts nobody.
Given n
and an array trust
, where trust[i] = [a<sub>i</sub>, b<sub>i</sub>] means person a<sub>i</sub> trusts person b<sub>i</sub>, return the label
of town judge. If there is no town judge, return -1.
Examples
Example 1:
- Input: n = 4, trust = [[1, 2], [3, 2], [4, 2]]
- Expected Output: 2
- Justification: Person 2 is trusted by persons 1, 3, and 4, and person 2 trusts no one. Hence, person 2 is the town judge.
Example 2:
- Input: n = 3, trust = [[1, 3], [2, 3]]
- Expected Output: 3
- Justification: Person 3 is trusted by persons 1 and 2, and person 3 trusts no one. Hence, person 3 is the town judge.
Example 3:
- Input: n = 3, trust = [[1, 3], [2, 1], [3, 1]]
- Expected Output: -1
- Justification: Person 1 is trusted by persons 2 and 3, but person 1 also trusts person 3. Thus, there is no town judge.
Constraints:
- 1 <= n <= 1000
- 0 <= trust.length <= 10<sup>4</sup>
- trust[i].length == 2
- All the pairs of trust are unique.
- a<sub>i</sub> != b<sub>i</sub>
- 1 <= a<sub>i</sub>, b<sub>i</sub> <= n
Try it yourself
Try solving this question here:
Python3
Python3
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