Grokking LinkedIn Coding Interview
0% completed
Hidden Document
Hidden Document Content Hidden Document Content Hidden Document Content Hidden Document Content Hidden Document Content Hidden Document Content Hidden Document Content Hidden Document Content Hidden Document Content Hidden Document Content Hidden Document Content Hidden Document Content Hidden Document Content Hidden Document Content Hidden Document Content Hidden Document Content Hidden Document Content Hidden Document Content Hidden Document Content Hidden Document Content Hidden Document Content Hidden Document Content Hidden Document Content Hidden Document Content
.....
.....
.....
Like the course? Get enrolled and start learning!
Nabeel Keblawi
· 2 years ago
I used only 2 lines of code, but it's O(n) space complexity not O(1) in the course solution. And it's also Python, which may not be doable in other languages.
tmp = ''.join([char for char in s if char.isalnum()]).lower() return tmp == tmp[::-1]