0% completed
Overview
The Dining Philosophers problem is a classic synchronization problem. The key challenge in the problem is to ensure that when a philosopher picks up one fork, they are guaranteed to get the other fork without causing a deadlock. Deadlocks can happen, for example, if each philosopher picks up the left fork simultaneously, waiting indefinitely for the right fork, which will never become available. Another concern is to avoid any philosopher from starving, meaning the system should be fair enough that every philosopher gets a chance to eat.
Step-by-step Algorithm
-
Initialize: Set up N philosophers sitting around a circular table. Place a fork between each pair of adjacent philosophers.
-
Forever loop for each Philosopher:
-
Think: Engage in a thinking activity. This could be for a random or set duration.
-
Acquire Forks:
- a. Wait until the left fork is available.
- b. Once the left fork is acquired, wait for the right fork to be available.
-
Eat: Once both left and right forks are acquired, the philosopher can eat. This activity could be for a random or set duration.
-
Release Forks:
- a. Put down the right fork.
- b. Put down the left fork.
-
Ensure Fairness: Design the algorithm in a way that ensures every philosopher gets an opportunity to eat, i.e., no philosopher should starve. One way to do this is by using an alternating sequence where odd and even philosophers pick up forks in a different order.
Algorithm Walkthrough
Let's walk through a dry run of the Dining Philosophers problem implemented above, with a special emphasis on the synchronization constructs. The code implements a classic synchronization problem where five philosophers are sitting at a table, with one fork between each pair of them. They can either think or eat. To eat, a philosopher needs both the fork to their left and the fork to their right.
Initialization
- Forks: Initialize five mutexes representing the forks. Each mutex is initially unlocked.
- Philosophers: Create five threads, each representing a philosopher.
Execution
For the sake of simplicity, we will describe the actions of a single philosopher in each state. These actions are occurring concurrently for all philosophers.
-
Thinking: The philosopher is in the thinking state. They print "Philosopher X is thinking." and then sleep for 1 second to simulate thinking time.
-
Hungry and Trying to Pick Up Forks:
- For Philosophers 0 to 3 (id < N-1): They try to pick up the left fork first. If the left fork (fork[id]) is available, they lock it (acquire the mutex). Then, they try to pick up the right fork (fork[(id+1) % N]). If it is available, they lock it.
- For Philosopher 4: To avoid a deadlock situation, Philosopher 4 will try to pick up the right fork first (fork[0]), and then the left fork (fork[4]).
- If any fork is not available, the philosopher waits, creating a situation where no philosopher can eat if all of them pick up one fork (deadlock). The implemented strategy prevents this deadlock.
-
Eating: Once both forks are acquired, the philosopher prints "Philosopher X is eating." and sleeps for 1 second to simulate eating time.
-
Putting Down Forks: After eating, the philosopher releases both forks (unlocks the mutexes), allowing other philosophers to use them.
-
Repeat: The philosopher goes back to thinking, and the cycle repeats.
Synchronization Aspects
- Mutex Locks for Forks: Ensures that only one philosopher can use a fork at a time.
- Deadlock Avoidance: The last philosopher picks up the forks in the opposite order from the others, preventing a deadlock situation where each philosopher is holding one fork and waiting for the other.
This walkthrough provides a simplified view of how the synchronization constructs (mutexes) are used to manage access to shared resources (forks) in the Dining Philosophers problem, ensuring safe and deadlock-free execution.
.....
.....
.....
Table of Contents
Contents are not accessible
Contents are not accessible
Contents are not accessible
Contents are not accessible
Contents are not accessible