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Problem 8: ZeroEvenOdd Multithreading Problem
Overview
In the ZeroEvenOdd problem, we aim to print a sequence in the format "01020304...". The challenge is that we have three different threads responsible for printing parts of this sequence: one prints zeros, one prints even numbers, and one prints odd numbers. Proper synchronization between these threads is crucial to ensure the sequence is printed correctly and without race conditions. Our task is to structure and synchronize the threads to print this sequence up to 2n collaboratively.
Step-by-step Algorithm
-
Initialize
- Start with the first number (0).
- Set up synchronization tools (locks, conditions, etc.).
-
Thread A (Zero Printer)
- Responsible for printing zeros.
-
Thread B (Even Number Printer)
- Prints even numbers in sequence.
-
Thread C (Odd Number Printer)
- Prints odd numbers in sequence.
-
Synchronization
- Ensure Thread A runs first, followed by either Thread B or Thread C based on whether the next number is even or odd.
-
Wrap-up
- Continue until the sequence length reaches
2n
.
- Continue until the sequence length reaches
Algorithm Walkthrough
Assume n = 2
. Our sequence should be "0102".
- Initialization:
- Set
n = 2
. - Initialize
counter = 1
.
- Set
- Zero Printing (
zero()
function):- Print "0" because it's the starting character of the sequence.
- Odd Printing (
odd()
function):- Since
counter
is 1 (odd), this thread prints "1". - Increment
counter
to 2. - Signal to the Zero thread by unlocking
zero_lock
.
- Since
- Zero Printing (
zero()
function):- Print "0" following the odd number.
- Even Printing (
even()
function):- With
counter
at 2 (even), this thread prints "2". - Signal the end of the sequence as
counter
now equalsn
.
- With
Synchronization Explained
- Zero Thread: No lock initially. Prints "0" and signals the Odd thread if the
counter
is odd, or the Even thread ifcounter
is even, by unlocking the respective lock. - Odd Thread: Initially locked. Waits for the Zero thread to signal. When unlocked, prints the odd number, increments
counter
, and signals back to the Zero thread by unlockingzero_lock
. - Even Thread: Initially locked. Waits for the Zero thread to signal after an odd number has been printed. When unlocked, prints the even number and signals back to the Zero thread.
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Python3
Python3
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