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Find Minimum in Rotated Sorted Array (medium)
Problem Statement
You have an array of length n
, which was initially sorted in ascending order. This array was then rotated x
times. It is given that 1 <= x
<= n. For example, if you rotate [1, 2, 3, 4]
array 3
times, resultant array is [2, 3, 4, 1]
.
Your task is to find the minimum element from this array. Note that the array contains unique elements.
You must write an algorithm that runs in O(log n)
time.
Example 1:
- Input: [8, 1, 3, 4, 5]
- Expected Output: 1
- Justification: The smallest number in the array is 1.
Example 2:
- Input: [4, 5, 7, 8, 0, 2, 3]
- Expected Output: 0
- Justification: The smallest number in the array is 0.
Example 3:
- Input: [7, 9, 12, 3, 4, 5]
- Expected Output: 3
- Justification: In this rotated array, the smallest number present is 3.
Constraints:
n == nums.length
1 <= n <= 5000
-5000 <= nums[i] <= 5000
- All the integers of nums are unique.
- nums is sorted and rotated between 1 and n times.
Try it yourself
Try solving this question here:
Python3
Python3
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