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My Calendar I (medium)
Problem Statement
Given a 2D array nums
of size N x 2
.
- nums[i] = [start<sub>i</sub>, end<sub>i</sub>], where start<sub>i</sub> is the starting time of the event and end<sub>i</sub> is the ending time of the event.
For each nums[i]
, determine if a requested booking time conflicts with any existing bookings.
Return a boolean array of size N
, representing whether the booking can be done in the given time interval.
Examples
-
Example 1:
- Input: nums = [[10, 20], [15, 25], [20, 30]]
- Expected Output:
[true, false, true]
- Justification: The first event is booked successfully. The second event overlaps with the first one and is rejected. The third event starts when the first event ends, so it's booked successfully.
-
Example 2:
- Input: [[5, 10], [10, 15], [5, 15]]
- Expected Output:
[true, true, false]
- Justification: The first and second events are booked without overlap. The third event overlaps with both the first and second, so it's rejected.
-
Example 3:
- Input: [[8, 13],[13, 17], [17, 20]]
- Expected Output:
[true, true, true]
- Justification: All events are booked without any overlap, as each event starts exactly when the previous one ends.
Constraints:
- 0 <= start < end <= 10<sup>9</sup>
- At most 1000 calls will be made to book.
Try it yourself
Try solving this question here:
Python3
Python3
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