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My solution
Mohammed Dh Abbas
Jul 16, 2024
#class Interval: # def __init__(self, start, end): # self.start = start # self.end = end # def print_interval(self): # print("[" + str(self.start) + ", " + str(self.end) + "]", end='') class Solution: def canAttendAllAppointments(self, intervals): def do_overlap(a, b): return b.start < a.end # sort the intervals first to compare the overlapping intervals intervals.sort(key = lambda x: x.start) for i in range(1, len(intervals)): # check the interval and the previous interval for overlapping if do_overlap(intervals[i - 1], intervals[i]): return False return True
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