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int count =0; HashMap hmap = new HashMap(); public int pathS...
Avinash Agarwal
Apr 6, 2022
int count =0; HashMap hmap = new HashMap();
public int pathSum(TreeNode root, int targetSum) { pathSum(root, 0, targetSum); return count; }
private void pathSum(TreeNode node, int curSum, int targetSum) { if(node == null) return;
curSum += node.val;
if(curSum == targetSum) count++;
count += hmap.getOrDefault(curSum-targetSum, 0);
hmap.put(curSum, hmap.getOrDefault(curSum, 0) + 1);
pathSum(node.left, curSum, targetSum); pathSum(node.right, curSum, targetSum);
hmap.put(curSum, hmap.get(curSum) -1); }
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Avinash Agarwal4 years ago
This is an O(N) solution
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