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Solution with only one loop
Enrique Fernández
Jan 2, 2025
class Solution: def findNumbers(self, nums): duplicateNumbers = [] # TODO: Write your code here i, n = 0, len(nums) while i < n: num = nums[i] if num != nums[num - 1]: nums[i], nums[num - 1] = nums[num - 1], nums[i] else: if num != i + 1: duplicateNumbers.append(num) i += 1 return duplicateNumbers
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