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Can't you just return slow value for the similar problem? Since we found that th...
Ada
Apr 10, 2022
Can't you just return slow value for the similar problem? Since we found that there is a cycle when they meet, then surely the duplicate is the value at the slow position, and thus no use for the find_start method? I just returned the slow value without using find_start and it still passes all the cases mentioned above.
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wuinko 3 years ago
Did the same too, wondering the samething
J
Jeff 3 years ago
This won't work, slow and fast will intersect at some point during the cycle, not necessarily at the start of the cycle. Take this case for example: [2,1,3,4,2]
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