Grokking the Coding Interview: Patterns for Coding Questions
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Easier solution to understand

Baraa Attabbaa

Aug 3, 2023

i,j,start,end = 0,0,0,1 while i<len(intervals_a) and j<len(intervals_b): a=intervals_a[i] b=intervals_b[j] interval = [max(a[start], b[start]), min(a[end], b[end])] if interval[start]<=interval[end]: result.append(interval) if (a[end] > b[end]): j+=1 else: i+=1

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