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It's more intuitive for me to keep track of the count of 0s instead. The conditi...
SeungJin Kim
Feb 27, 2022
It's more intuitive for me to keep track of the count of 0s instead. The condition then will be 'if zero count > k:'
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Richard Yuan3 years ago
I agree and that's how I solved it as well. However, I think they wrote the solution this way so it is similar to the previous problem. So by comparing the elements to be replaced with k in both problems, it would hopefully be easier to remember.
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