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This is the same solution but with Return Early.
Dakshesh Jain
Mar 19, 2024
This is the same solution but with Return Early, many programmers myself included find this more readable.
class Solution: def diffWaysToEvaluateExpression(self, input): result = [] # return early instead of using else condition if "+" not in input and "*" not in input and "-" not in input: result.append(int(input)) return result # continue program if condition is not met for i in range(len(input)): char = input[i] if char.isdigit(): # this also avoids nesting continue left_part = self.diffWaysToEvaluateExpression(input[0:i]) right_part = self.diffWaysToEvaluateExpression(input[i+1:]) for part_1 in left_part: for part_2 in right_part: if char == "+": result.append(int(part_1 + part_2)) elif char == "*": result.append(int(part_1 * part_2)) elif char == "-": result.append(int(part_1 - part_2)) return result
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Silencer312 2 years ago
I mean its the same thing
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