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Problem Challenge 1: Reverse alternating K-element Sub-list (medium)
Problem Statement
Given the head of a LinkedList and a number k, reverse every alternating k sized sub-list starting from the head.
The first k nodes are reversed, the next k are left alone, the next k are reversed, and so on.
If the last group holds fewer than k nodes, treat it the same way as a full group: reverse it if it
falls on a reversing turn, leave it alone if it falls on a skipping turn.
Example:
Input: 1 -> 2 -> 3 -> 4 -> 5 -> 6 -> 7 -> 8 -> 9 -> 10 -> null, k = 3
Output: 3 -> 2 -> 1 -> 4 -> 5 -> 6 -> 9 -> 8 -> 7 -> 10 -> null
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dos
· 22 days ago
Why my saved code just disappeared ? seems you have TTL for the code submitted. is there any way to restore ?
Shaho Shahbazpanahi
· a year ago
For this input [1,2,3,4,5,6,7,8,9,10,11] and k= 3, then expected output should be [3,2,1,6, 5, 4,10, 8,9,11, 10] while the solution give us [3,2,1,6, 5, 4,10, 8,9, 10, 11] , the problem stats if the rest of lis is smaller than k, revese it to .
Lucas
· 4 years ago
Here is my solution! Hope it doesnt crack under pressure :)

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