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Solution: Problem Challenge 1: Flip and Invert an Image
Problem Statement
Given a binary matrix representing an image, we want to flip the image horizontally, then invert it. Every row has the same number of columns.
To flip an image horizontally means that each row of the image is reversed. For example, flipping [0, 1, 1] horizontally results in [1, 1, 0].
To invert an image means that each 0 is replaced by 1, and each 1 is replaced by 0. For example, inverting [1, 1, 0] results in [0, 0, 1].
Example 1:
Input: [
[1,0,1],
[1,1,1],
[0,1,1]
]
Output: [
[0,1,0],
[0,0,0],
[0,0,1]
]
.....
.....
.....
Naveen Gupta
· 2 years ago
class Solution: def flipAndInvertImage(self, matrix): for row in range(len(matrix)): matrix[row] = [abs(i-1) for i in matrix[row][::-1]] return matrix
lejafilip
· 2 years ago
Tbh it is not hard question but it is just my opinion.
J
· 4 years ago
Time complexity should be O(N^2) is input matrix is guaranteed to be a square or O(M * N) if not.
Pete Stenger
· 4 years ago
The solution given assumes the matrix is square. Update C to be len(matrix[0]) or add the constraint.
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