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“ After executing a task we decrease its frequency and put it in a waiting list....
Akaash
Jan 29, 2023
“ After executing a task we decrease its frequency and put it in a waiting list. In each iteration, we will try to execute as many as k+1 tasks.”
Would be good to explain why and how we get k+1 here. I’m not sure I follow.
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Design Gurus3 years ago
It is based on the problem requirement, "the cooling period for all tasks is ‘K’ intervals."
Once we execute a task, we have to wait for 'K' intervals before we could execute it again.
K
k 2 years ago
a _ _ a = 2 cooling intervals = 3 Distance apart.