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Confusion on the Solution (Java)
Adrian Harischand
Jul 13, 2023
Greetings, can someone please explain why are we doing : result.add(new ArrayList<>(tempList)); instead of result.add(tempList); . I notice that there is a difference in output when we do this but why is that ?
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zaid 2 years ago
because its passed by reference so what will happen. you need to create a new instance of the list because if you don't, you will update the tempList thats inside the result list
In Java, when you pass an object (like an ArrayList) to a method or add it to another co...