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Simpler solution
Mohammed Dh Abbas
Jul 11, 2024
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Jul 11, 2024
Hey, thanks for this course in general and for the good explanations.My question...
Viktor
Oct 27, 2022
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Oct 27, 2022
I don't understand the purpose of minLength? like it is the length of the entire...
Alan Ross
Oct 6, 2022
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Oct 7, 2022
I don't think the reason why we need to check "if min_length > window_end - wind...
Bharpur Singh
Sep 20, 2022
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15
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Sep 20, 2022
I don't think the reason why we need to check "if min_length > window_end - wind...
Bharpur Singh
Sep 20, 2022
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Jul 22, 2024
Hi, most of this makes sense besides the following line.`if (charFrequencyMap.ge...
John Moon
Sep 14, 2022
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Sep 19, 2022
I am also failing to understand the time complexity of the algo. I understand th...
aj
Jun 16, 2022
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Aug 1, 2022
if (charFrequencyMap.get(rightChar) >= 0) // count every matching of a character...
aj
Jun 16, 2022
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19
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Jun 16, 2022
Hi everyone, is there any disadvantage to using the same conditions as the previ...
Gideon
Mar 24, 2022
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8
8
Dec 5, 2022
For anyone struggling understanding the provided solution, I suggest looking at...
Nick
Mar 15, 2022
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Jul 13, 2022
I feel this problem needs another example such as:s="ab", p="a"This additional e...
nrstnbr
Mar 14, 2022
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5
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Mar 14, 2022
The problem statement feels a bit ambiguous to me, and the examples aren't helpi...
hj3yoo
Feb 20, 2022
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8
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Feb 20, 2022
My solution, time complexity is O(N+M) public String minWindow(String s, Stri...
Syed Hassan
Jan 17, 2022
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8
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Mar 14, 2022