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Binary Tree Path Sum (easy)
Problem Statement
Given a root
of the binary tree and an integer ‘S’, return true
if the tree has a path from root-to-leaf such that the sum of all the node values of that path equals ‘S’. Otherwise, return false
.
Examples
Example 1:
- Input: root =
[1, 2, 3, 4, 5, 6, 7]
, S =10
- Expected Output:
true
- Justification: The tree has
1 -> 3 -> 6
root-to-leaf path having sum equal to 10.
Example 2:
- Input: root =
[12, 7, 1, 9, null, 10, 5]
, S =23
- Expected Output:
true
- Justification: The tree has
12 -> 1 -> 10
root-to-leaf path having sum equal to 23.
Example 3:
- Input: root =
[12, 7, 1, 9, null, 10, 5]
, S =16
- Expected Output:
false
- Justification: The tree doesn't have root-to-leaf path having sum equal to 16.
Constraints:
- The number of nodes in the tree is in the range
[0, 5000]
. -1000 <= Node.val <= 1000
-1000 <= targetSum <= 1000
Try it yourself
Try solving this question here:
Python3
Python3
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