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Pseudo-Palindromic Paths in a Binary Tree (medium)
Problem Statement
Given a binary tree where each node has a value between 1
and 9
, return the number of "pseudo-palindromic"
paths from the root node to any leaf node.
A path is called "pseudo-palindromic"
if the values along the path can be rearranged to form a palindrome.
Examples
Example 1
- Input:
5 / \ 4 1 / \ \ 4 1 1
- Expected Output: 2
- Justification: The paths are:
- 5 → 4 → 4 (pseudo-palindromic: "5, 4, 4" can be rearranged to "4, 5, 4")
- 5 → 1 → 1 (pseudo-palindromic: "5, 1, 1" can be rearranged to "1, 5, 1")
Example 2
- Input:
2 / \ 3 1 / / \ 3 1 1
- Expected Output: 3
- Justification: All 3 paths are pseudo-palindromic paths.
Example 3
- Input:
9 / \ 5 5 / / \ 5 1 7
- Expected Output: 1
- Justification: The only path 9 → 5 → 5 is a psuedo-palindromic path.
Constraints:
- The number of nodes in the tree is in the range [1, 10<sup>5</sup>].
- 1 <= Node.val <= 9
Try it yourself
Try solving this question here:
Python3
Python3
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Problem Statement
Examples
Try it yourself