Dear authors...Why are the sample solutions so unwieldly hard to read?

My solution

Using Object.keys() for iterating increases time complexity

Soloution is buggy

use set instead of hashMap

This is one that is causing me a lot of trouble https://leetcode.com/problems/sl...

I didn't really get the window " In the current window, ...." . Can anyone expl...

I believe I accounted for the edge cases...As long as you encounter a letter you...

Can someone give me some feedback on this?

As discussed below here is the solution similar to that in example but with if i...

I would like add two point. 1. The while loop is not necessary, because we are ...

Can someone clarify this line: maxLength = Math.max(maxLength, windowEnd ...

Why not use Sliding Window + Ordered Dictionary?

"aabccbbdef" is a good example that will trigger the edge case. As mentioned by ...

A less tricky solution would be to check if the frequency of the current charact...

how about this solution, basically once we encounter a duplicate then just clea...

Hello, is the hashmap even needed? Can't you just get the first character in the...

Out of curiosity, why is the time complexity O(N) and not O(N*K)

Anything wrong with this solution? Thanksstatic int longestSubstring(String inpu...

Hi, For "Longest Substring with K Distinct Characters" question, curious to kno...

Why is right_char frequency initialized to 0 as we add it to the char_frequency ...

Does anybody have an edge case where you need to set windowStart like thiswindow...

Why do we need to delete the leftCharacter once its frequency reaches 0?

windowStart = Math.max(windowStart, charIndexMap.get(rightChar) + 1);Any...

An implementation in golang based on maintaining character count instead of char...

A simple implementation using Arrays instead of hashmap. It uses a fixed size a...

Its bit difficult to my head get around this implementation since in the previou...

Why can't you insert rightChar into the map first and then update widowStart, su...