
Sum of Subarray Minimums (medium)
Problem Statement
Given an array of integers arr, return the sum of the minimum values from all possible contiguous subarrays within arr. Since the result can be very large, return the final sum modulo (10<sup>9</sup> + 7).
Examples
Example 1:
- Input: arr =
[3, 1, 2, 4, 5] - Expected Output:
30 - Explanation:
- The subarrays are:
[3],[1],[2],[4],[5],[3,1],[1,2],[2,4],[4,5],[3,1,2],[1,2,4],[2,4,5],[3,1,2,4],[1, 2, 4, 5],[3, 1, 2, 4, 5]. - The minimum values of these subarrays are:
3, 1, 2, 4, 5, 1, 1, 2, 4, 1, 1, 2, 1, 1, 1. - Summing these minimums:
3 + 1 + 2 + 4 + 5 + 1 + 1 + 2 + 4 + 1 + 1 + 2 + 1 + 1 + 1 = 30.
- The subarrays are:
Example 2:
- Input: arr =
[2, 6, 5, 4] - Expected Output:
36 - Explanation:
- The subarrays are:
[2],[6],[5],[4],[2,6],[6,5],[5,4],[2,6,5],[6,5,4],[2,6,5,4]. - The minimum values of these subarrays are:
2, 6, 5, 4, 2, 5, 4, 2, 4, 2. - Summing these minimums:
2 + 6 + 5 + 4 + 2 + 5 + 4 + 2 + 4 + 2 = 36.
- The subarrays are:
Example 3:
- Input: arr =
[7, 3, 8] - Expected Output:
35 - Explanation:
- The subarrays are:
[7],[3],[8],[7,3],[3,8],[7,3,8]. - The minimum values of these subarrays are:
7, 3, 8, 3, 3, 3. - Summing these minimums:
7 + 3 + 8 + 3 + 3 + 3 = 27.
- The subarrays are:
Constraints:
- 1 <= arr.length <= 3 * 10<sup>4</sup>
- 1 <= arr[i] <= 3 * 10<sup>4</sup>
Try it yourself
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Python3
Python3
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