
Spiral Matrix (medium)
Problem Statement
Given a 2D matrix of size m x n, return the 1D array containing all elements of matrix in spiral order.
Examples
Example 1:
- Input: matrix =
[[1,2,3,4],
[5,6,7,8],
[9,10,11,12],
[13,14,15,16]]
- Expected Output:
[1,2,3,4,8,12,16,15,14,13,9,5,6,7,11,10] - Justification: We have traversed the matrix in the spiral order.
Example 2:
- Input: matrix =
[[10,20,30],
[40,50,60],
[70,80,90]]
- Expected Output:
[10,20,30,60,90,80,70,40,50] - Justification: The traversal starts at the top-left, moves right to the end of the row, then down the right column, then left along the bottom row, up the left column, and finally captures the center.
Example 3:
- Input: matrix =
[[1,2],
[3,4],
[5,6]]
- Expected Output:
[1,2,4,6,5,3] - Justification: The traversal starts at the top-left, moves right, then down through the right column, and finally moves up the left column.
Constraints:
- m == matrix.length
- n == matrix[i].length
- 1 <= m, n <= 10
- -100 <= matrix[i][j] <= 100
Try it yourself
Try solving this question here:
Python3
Python3
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